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2x^2+4x-646=0
a = 2; b = 4; c = -646;
Δ = b2-4ac
Δ = 42-4·2·(-646)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-72}{2*2}=\frac{-76}{4} =-19 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+72}{2*2}=\frac{68}{4} =17 $
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